Thursday, October 21, 2021

Leet Code Solution JAVA - Guess Number Higher or Lower

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.

You call a pre-defined API int guess(int num), which returns 3 possible results:

  • -1: The number I picked is lower than your guess (i.e. pick < num).
  • 1: The number I picked is higher than your guess (i.e. pick > num).
  • 0: The number I picked is equal to your guess (i.e. pick == num).

Return the number that I picked.

 

Example 1:

Input: n = 10, pick = 6
Output: 6

Example 2:

Input: n = 1, pick = 1
Output: 1

Example 3:

Input: n = 2, pick = 1
Output: 1

Example 4:

Input: n = 2, pick = 2
Output: 2

 

Constraints:

  • 1 <= n <= 231 - 1
  • 1 <= pick <= n

My Code:

/** 
 * Forward declaration of guess API.
 * @param  num   your guess
 * @return      -1 if num is lower than the guess number
 *       1 if num is higher than the guess number
 *               otherwise return 0
 * int guess(int num);
 */

public class Solution extends GuessGame {
    public int guessNumber(int num) {
        int i=1, j=num, mid=1;
        
        while(i<=j){
            mid = i + (j-i) / 2;
            int result = guess(mid);
            if(result==1) i = mid+1;
            else if (result==-1) j = mid-1;
            else return mid;
        }
        
   
        return mid;
    }
}
Copyright © saras ojha

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