Leet Code JAVA Solution - Angle Between Hands of a Clock

Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.

 

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

Example 4:

Input: hour = 4, minutes = 50
Output: 155

Example 5:

Input: hour = 12, minutes = 0
Output: 0

 

Constraints:

• 1 <= hour <= 12
• 0 <= minutes <= 59
• Answers within 10^-5 of the actual value will be accepted as correct.

My Code:

class Solution {

    public double angleClock(int hour, int minutes) {

        double angle = 5.5*(minutes + (hour)*60);

          if (angle < 360 && angle > 180){

           return (360 -angle);

        }

        else if (angle>360){

            double n = angle%360;

            if(n>180){

                return (360 - n);

            }

            else{

                return n;

            }

        }

        else if(angle<0){

            return (-angle);

        }

       return 0; 

    }

    

}

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